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S.H.M. numerical plz help!!I need help with the concept of this problem. " THE SHORTEST DISTANCE TRAVELLED BY A PARTICLE MOVING IN SHM FROM ITS MAIN POSITION IN 2 SECONDs is (3^0.5 / 2) OF ITS AMPLITUDE. FIND THE TIME PERIOD.I can easily solve it by using the eqn of motion : x = a sin (wt). And in that case period is 12 seconds. I just want to know, 'what if I use the eqn x = a cos(wt)'? Then T changes. But why? Plz help!!Thank you!
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