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a wire of resistance 5 ohm is drawn out to its new length, three times its original length. the resistance of new wire is..
Dear studentR =þ * l / AVolume is constantl *A = 3 l * A/3So5 =þ l/ARnew = 9 * 5 = 45 ohmsRegards
Dear student R1 = 5 ohm l1 = l l2 = 2lWhen wire is stretched V1 = V2 A1l1 = A2l2 A2 = A1/2R1/R2 = 1/4 R2 = 4R1
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