Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A wire of resistance 10 ohm is stretched 20% determinant its new resistance

A wire of resistance 10 ohm is stretched 20% determinant its new resistance
 

Grade:12th pass

2 Answers

Arun
25763 Points
one year ago
resistance is given by, R = ρl/A
 
R = ρl²/(Al) = ρl²/V.....(1), where V is volume of wire.
 
at constant volume, V resistance of wire depends on only length of wire.
 
as it is clear in expression (1), resistance is directly proportional to square of its length.
 
now, according to question,
 
length is increased by 20%
 
so, new length of wire = l + 20% of l
 
= l + 0.2l = 1.2l
 
now, new resistance , R' = ρ(1.2l)²/V....(2)
 
from equations (1) and (2),
 
R'/R = 1.44 => R' = 1.44R
 
it is given initial resistance, R = 10ohm
 
so, R' = 1.44R = 14.4ohm
 
 
Vikas TU
14149 Points
one year ago
Dear student 
resistance is given by, R = ρl/A
R = ρl²/(Al) = ρl²/V.....(1), where V is volume of wire.
at constant volume, V resistance of wire depends on only length of wire.
as it is clear in expression (1), resistance is directly proportional to square of its length.
now, according to question,
length is increased by 20%
so, new length of wire = l + 20% of l
= l + 0.2l = 1.2l
now, new resistance , R' = ρ(1.2l)²/V....(2)
from equations (1) and (2),
R'/R = 1.44 => R' = 1.44R
Good Luck 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free