A wire has resistance of 3.1 ohm at 30°C and 4.5 ohm at 100°C .The temperature coefficient of resistance to the wire is ...?

Question

Sanju · Answer

R 1 = 3.1 ohm at t = 30 0 C R 2 = 4.5 ohm at t = 100 0 C We have, R = R 0 (1+ &alpha; t) So, R 1 = R 0 (1+ &alpha; * 30 ) R 2 = R 0 (1+ &alpha; * 100 ) R 1 / R 2 = [(1+30 &alpha; ) / (1+100 &alpha; )] 3.1 /4.5 = [(1+30 &alpha; ) / (1+100 &alpha; )] Solving the above expression gives: Temp. coefficient, &alpha; = 0.0085 0C -1

ankit singh · Answer

R 1 = R 0 (1+ α * 30 ) R 2 = R 0 (1+ α * 100 ) R 1 / R 2 = [(1+30 α ) / (1+100 α )] 3.1 /4.5 = [(1+30 α ) / (1+100 α )] solve for coefficient

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A wire has resistance of 3.1 ohm at 30°C and 4.5 ohm at 100°C .The temperature coefficient of resistance to the wire is ...?

A wire has resistance of 3.1 ohm at 30°C and 4.5 ohm at 100°C .The temperature coefficient of resistance to the wire is ...?

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