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        A uniform wire of resistance 4 ohm is bent into a circle of radius r. A specimen of the same wire is connected along the diameter of the circle. What is the eq resistance?
3 years ago

Umakant biswal
5349 Points
							@ surabhi i think the data given is insuficient to calculate the equivalent resistance . its not mentioned that the speciman wire have resistance or not . so, i am assuming it to be present of 4 ohm of resister . if so, thenit will be parallel combination of two resisters of4 ohm each /. so,, acc to the formula 1/ R (EQUI ) = 1/R1 + 1/R2 SO, 1/R = 1/4+1/41/R= 2/4 = ½  so, r = 2 ohm HOPE U ARE CLEARS NOW IF ANSWER ISGIVEN SOMETHING DIFFRENT THEN LETME KNOW ALL THE BEST ..

3 years ago
Raman Mishra
67 Points
							Let the resistance per unit length be $\dpi{80} \lambda$. Then,
$\dpi{80} \lambda$ = 4/$\dpi{80} 2\pi r$
=> resistance of the specimen wire connected along the diameter is:
$\dpi{80} R = \lambda \times 2r = \frac{4}{\pi } \Omega$
Now after the specimen wire is connected along the diameter, three resistance come in parallel:
$\dpi{80} 2 \Omega$ (resistance of one half of the circumference),  $\dpi{80} 2 \Omega$ (resistance of the other half of the circumference) and R(resistance of the diameter). Solving, we get:
$\dpi{80} {\color{DarkRed}R_{eq} = \frac{4}{4+\pi } \Omega }$
Hope you understood dear Surabhi.

3 years ago
RANJEET KUMAR
32 Points
							dear umakant bro..u do not have basic understanding of english neither you know physics well. please do not mislead students if you do not know the answer.

3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions