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A storage battery of EMF 8V, internal resistance 1 ohm is being charged by 120 V D.C. source using a 15 ohm resistor in series in the circuit. Calculate (i)current in the circuit (ii)terminal voltage of the battery (iii)chemical energy stored in the battery in 5 minutes
Since the battery would in parallel to the 8v and internal resistance 1 ohm and the 15 ohm resistance with series,the battery purpose would only have to charge the 8 volt Emf, Hence the current drawn in the circuit would be:I = 8/(1+15) = 0.5 A. Terminal battery Voltage = > 8 – Ir => 8 – 0.5*1 = > 7.5 Voltage.Heat = I^2(Rnegt)*t => 0.25*16*5*60 => 1200 Joule.
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