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a battery of 10v and negligible internal resistance is coonected across the diagonally opposite corners of a cubical network consisting of 12 resistors each of resistanvce 1ohm. the currnt through the battery is?
Dear Garima Please attach the image as it is required to answer this question. I will be happy to help you. RegardsArun
efective across the diagonally opposite corners of a cubical network consisting of 12 resistors each of resistanvce 1ohm = 5/6 ohmThen current through battery = V/R = 10/(5/6) = 12 AHope it clears.
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