A positively charged ball hangs from a long silk thread. We put a positive test charge q0 at a point and at a

point and measure F/q0, then it can be predicted that field E

(a) > F/q0 (b) is equal to F/q0 (c) < F/q0

Because of the presence of positive test charge q₀

decrease i.e., Actual Electric field will be greater than F/q₀

, in front of positively charged ball, charge 

on the ball will be redistributed, less charge on the front half surface & more charge on the

back half surface. As a result of this net force F between ball and point charge will