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In order to inc the resistance of a given wire of uniform cross section to four times it's value, a fraction of length of the wire becomes 3/2 times the original length. Show that the value of this fraction is 1/8.

```
11 years ago

Pratham Ashish
17 Points
```							Hi,

tushar der is smtng wrong with ur question.

Let us consider that v increase the length of the whole wire to 3/2 times of it original length ,

still the R wud become 9/4 R.IT can't be 4R in any case.

Consider length is increase to 3/2 times,then its cross section area will become 2/3 times of its original,

the resistance is proportional to length and inversly proportional to area ,

hence the new resistance wud b {(3/2L)/(2/3A)}=9/4*L/A = 2.25R.

So i request u to plz confirm ur qn & repost ur doubt.

```
11 years ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions