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Kuldeep Mukherjee Grade: 12
        An electric field of 200 V/m exists in the region between the places of the parallel plate capacitor of plate separation 5 cm.(a) Find the potential difference between the plates when a slab of dielectric constant 4 and thickness 1 cm is inserted parallel to plates.

(b)The slab is now replaced by a metal plate of thickness x cm.Find the value of x such that the potential difference between the plates remains the same as in case (a)
7 years ago

Answers : (1)

879 Points

Dear student,

\begin{displaymath} E_x = - \frac{dV}{dx}. \end{displaymath}

We call the quantity $dV/dx$ the gradient of the electric potential in the $x$-direction. It basically measures how fast the potential $V$ varies as the coordinate $x$ is changed (but the coordinates $y$ and $z$ are held constant). Thus, the above formula is saying that the $x$-component of the electric field at a given point in space is equal to minus the local gradient of the electric potential in the $x$-direction.


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Askiitians Expert

Sagar Singh

B.Tech, IIT Delhi

7 years ago
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