the uniform electric field vector in space is given as 3i + 4 j + 5 k . what is the electric flux through a a circle of radius 5 m. if the circle lies in y - z plane. . . .. . . pls help . .the options are a)100 b)75 c)zero . . . . . .plese help

Dear Laique,

Ans:- The area vector is=A= ∏r² i =25∏

E=3i+4j+5k

Flux=E.A=75∏ (ans)

Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
are all IITians and here to help you in your IIT JEE preparation.

All the best Laique !!!

Regards,

Askiitians Experts

SOUMYAJIT IIT_KHARAGPUR

Approved