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`        The number of triplets of positive integers {a,b,c} such that a*b*c = 2310`
one year ago

Arun
22584 Points
```							Dear shubham
2310 = 2 X 3 X 5 X 7 X 11

A non-trivial factor is a factor other than 1.
If there is only one non-trivial factor, then the triplet is (1,1,2310)
If there is one trivial factor, then we are looking for ways to factorise 2310 into two factors
If no trivial factor, then 2310 is to be factorised into three factors.
i.e. the numbers 2,3,5,7,11 are to be divided into two and three groups respectively. Here the concept of Stirling numbers of the second kind comes into play. Check out http://en.wikipedia.org/wiki/Stirling_numbers_of_the_second_kind
Hence, the number of triplets is 1+ S(5,2)+S(5,3) = 41

```
one year ago
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• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions