show that area of equilateral triangle inside a circle x^2+y^2+2gx+2fy+c=0 is 3√3/4

Question

Saurabh Koranglekar · Answer

Dear student

Please note the equation of circle contains unknowns (f,g,c) hence it is not possible.
however area of an equilateral triangle is (sqrt3)(side^2)/4, just find out any side and you may prove the statement

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show that area of equilateral triangle inside a circle x^2+y^2+2gx+2fy+c=0 is 3√3/4

show that area of equilateral triangle inside a circle x^2+y^2+2gx+2fy+c=0 is 3√3/4

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show that area of equilateral triangle inside a circle x^2+y^2+2gx+2fy+c=0 is 3√3/4

show that area of equilateral triangle inside a circle x^2+y^2+2gx+2fy+c=0 is 3√3/4

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