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Enthalpy of combustion of carbon is -393.5 k j mol^-1.calculate the amount of heat released upon formation of35.2 gm of CO2 from carbon and dioxygen gas.

6 years ago

Answers : (3)

Sunil Kumar FP
askIITians Faculty
183 Points
							
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thanks and regards
sunil kr
askIItian faculty

6 years ago
Aarti Gupta
askIITians Faculty
300 Points
							Enthalpy of combustion of carbon , delcH = -393.5 kJ/mol
Amount of CO2 = 35.2gm
C + O2 ------------> CO2
no. of moles = Mass/ Molar mass = 35.2/44 = 0.8 moles
thus heat released will be = -393.5 * 0.8 = -314.8 kj
Thanks & Regards
Aarti Gupta
askiitians Faculty
6 years ago
Robin Chourasia
askIITians Faculty
9 Points
							

C + O2 -> CO2

moles of CO2= 35.2/44=.8 moles of C02 formed

Heat released = .8 * 393.5 = 314.8 Kj

Thanks and Regards,

Robin

askIITian Faculty


6 years ago
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