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A small block of mass m moving on a smooth track connected with a circular track of radius R. If it starts from rest at P, what is the resultant force acting on it at Q

A small block of mass m moving on a smooth track connected with a circular track of radius R. If it starts from rest at P, what is the resultant force acting on it at Q

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Grade:12th pass

1 Answers

ph_2000
16 Points
6 years ago
At Q velocity of block, v,
1/2mv^2 = mg(5R-R)
v^2 = 8gR
now, forces acting on the block are,
mg downwards and mv^2/R to the right
therefore resultant F = under root[(mg)^2 + (8mg)^2]
    = under root[65(mg)^2]
    = root[65] mg
sorry, dont hve the symbol for under root.

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