A boll is released from height h.along the slope and move along a circular track of radius R without falling vertically downward as shown in figure show that h=5/2

Question

Arun · Answer

Dear student PE = KE mgh= ½ mV^2 mgh = 5/2 mgR h = 5R/2 hope it helps in case of any difficulty please feel free to ask. Regards Arun

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A boll is released from height h.along the slope and move along a circular track of radius R without falling vertically downward as shown in figure show that h=5/2

A boll is released from height h.along the slope and move along a circular track of radius R without falling vertically downward as shown in figure show that h=5/2

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A boll is released from height h.along the slope and move along a circular track of radius R without falling vertically downward as shown in figure show that h=5/2

A boll is released from height h.along the slope and move along a circular track of radius R without falling vertically downward as shown in figure show that h=5/2

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