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A 20.00-mL of sample containing Al+3 and Zn+2 required 13.13 mL of 0.045M EDTA for complete titration. A 50 mL of sample was treated with NH4F to protect the Al+3. Then Zn+2 was reduced with thiourea. Addition of 25 mL of 0.045 M EDTA liberated Al+3 from its fluoride complex to form the Al-EDTA complex. The excess EDTA required 18.65 mL of 0.01883M Pb+2 to reach the xylenol orange end point. Find [Zn+2] in the unknown.

A 20.00-mL of sample containing Al+3 and Zn+2 required 13.13 mL of 0.045M EDTA for
complete titration. A 50 mL of sample was treated with NH4F to protect the Al+3. Then Zn+2 was
reduced with thiourea. Addition of 25 mL of 0.045 M EDTA liberated Al+3 from its fluoride
complex to form the Al-EDTA complex. The excess EDTA required 18.65 mL of 0.01883M
Pb+2 to reach the xylenol orange end point. Find [Zn+2] in the unknown.

Grade:12

1 Answers

Arun
25750 Points
3 years ago
Dear student
 
the language of this question is not clear so please check and repost the question you can also attach an image I will be happy to help you

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