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Grade: 12th Pass

                        

A liquid soap film in shape of a plane loop has an initial area 0.05 m2. If its area is slowly doubled then the increase in its surface potential energy from its initial value will be (Surface tension of liquid = 0.2 N/m).

9 years ago

Answers : (2)

vikas askiitian expert
509 Points
							

dE  = Tds                 

T = surface tension , ds change in area

     =(0.05)2(0.2) = 2*10-3 joules

9 years ago
SATYAM JAISWAL
15 Points
							
U= Ts×Area
=2×0.2×0.05= 2×10-2J
 
This is correct answer . In this question we take a change in area and we multiplied by 2 because soap drop has two layer and surface tension is given so easily you will get answer.
 
Regards, 
Satyam Jaiswal

one year ago
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