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A liquid soap film in shape of a plane loop has an initial area 0.05 m2. If its area is slowly doubled thenthe increase in its surface potential energy from its initial value will be (Surface tension of liquid = 0.2N/m).

Vikas TU , 13 Years ago
Grade 12th Pass
anser 2 Answers
vikas askiitian expert

Last Activity: 13 Years ago

dE  = Tds                 

T = surface tension , ds change in area

     =(0.05)2(0.2) = 2*10-3 joules

SATYAM JAISWAL

Last Activity: 6 Years ago

U= Ts×Area
=2×0.2×0.05= 2×10-2J
 
This is correct answer . In this question we take a change in area and we multiplied by 2 because soap drop has two layer and surface tension is given so easily you will get answer.
 
Regards, 
Satyam Jaiswal

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