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a) pB0 = 300 torr pB0 = 800 torr
yA = pA/P = pA0xA/P
where yA and yB are mole fraction of A and B in the vapour
yB = pB0xA/P
∴ yA = yB = pB0xA/pB0xB
0.025/0.75 = 300xA/800xB
i.e., xA/xB = 8/9
i.e., xA = 8/17 = 0.47
Composition of last drop:
xB = 9/17 = 0.53
(B) Pressure of last drop:
p = pA0xA + pB0xB
(c) At boiling point: p = 760
760o = 300 xA + 800 (1−xA)
xA = 0.08, ∴ xB = 0.92
(d) For last drop: xA = 0.25, xB = 0.75
P = 300 × 0.25 + 800 × 0.75 = 675 torr.
(e) yA = pA/P
yA = 300×0.25/675 = 0.111
yB = 0.889
Here, yA and yB are composition of vapour of last drop.
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