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Please sir help me with this question. I am posting this 10th time.It is from AIATS.Please sir solve it ,I tried it many days but I failed to solve it,so plssss. Plsssss solve it.I got anwer but in that equation was written as F_string+F_hinge=Mg which was not possible bcz both the forces are acting in opposite direction. Please solve it,I am posting this question from many days.

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Kaushki

7 Years agoGrade 12th pass

1 Answer

neeraj

Approved Tutor Answer7 Years ago

before snapping the string,the tension in the string are,

2T=mg=mg/2

torque on the rod is,

T=mg(1/2)=I alpha=mgl/2=1/3ml(square)(alpha)=mgl/2=alpha=3g/2l

so the acceleration with which the centre of mass falls down is ,

a=l(alpha)/2=3g/4

so,

ma=f(down)-f(up)=m 3g/4=mg-T’=T=mg-3mg/4

T’=mg/4

Please send the full solution as soon as possible 🙏

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