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`        if a b c d are consecutive odd number then (a^2+b^2+c^2+d^2) is always divisible by?`
one year ago

## Answers : (2)

Shashank Singh
57 Points
```							let the 4 consecutive odd numbers are (2n-3), (2n-1), (2n+1), (2n+3)a^2+b^2+c^2+d^2= (2n-3)^2+ (2n-1)^2+(2n+1)^2+(2n+3)^22[(4n^2+9)+(4n^2+1)]4(4n^2+5)therefore it will be always be divisible by 4.
```
one year ago
sahil
142 Points
```							it will be always divisible by to as squate of odd no is odd and thereafter sum of 4 odd is even .So sum is even and divisible by 2.
```
one year ago
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• Previous Year Exam Questions