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Grade: 10
        
if a b c d are consecutive odd number then (a^2+b^2+c^2+d^2) is always divisible by?
11 months ago

Answers : (2)

Shashank Singh
askIITians Faculty
57 Points
							let the 4 consecutive odd numbers are (2n-3), (2n-1), (2n+1), (2n+3)
a^2+b^2+c^2+d^2= (2n-3)^2+ (2n-1)^2+(2n+1)^2+(2n+3)^2
2[(4n^2+9)+(4n^2+1)]
4(4n^2+5)
therefore it will be always be divisible by 4.
11 months ago
sahil
142 Points
							it will be always divisible by to as squate of odd no is odd and thereafter sum of 4 odd is even .So sum is even and divisible by 2.
						
11 months ago
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