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Bond energy of H-H is 104 kcal/mol,X-X is 60 kcal/mol,H-X is 101 kcal/mol Electronegativity of H is 2.1 What is the electro negativity of X?


2 years ago

Arun
24742 Points
							Dear Student Actual Bond energy $\Delta$ = EH-X – $\sqrt$EH-H * EX-X = 101 – $\sqrt$104* 60 = 22.01 Kcal/mol Electro negativity deiiference isXH – Xx  = 0.208 $\sqrt$$\Delta$2.1 –  Xx  = 0.208 * $\sqrt$22.01 Xx  = 1.12hence electronegativity of unknown atom is 1.12 RegardsArun (askIITians forum expert)

2 years ago
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