A target is fixed on top of a pole 13 m high. A person standing at a distance 50 m from the pole is capable of projecting a stone with velocity 10*rootg(underroot 9.8 m/s^2). If his aim is to strike the target in least time what should be the angle of elevation with time

Question

Arun Kumar · Answer

Hello Student,

y=13=vsintheta*t-1/2gt^2

x=50=vcostheta*t

we need to find dtheta/dt

from 1^stequation

0=vcostheta*t*dtheta/dt+vsintheta-gt

from second eq.

0=-vsintheta*t*dtheta/dt+vcostheta

we need to do dtheta/dt=0

=>vcostheta=0 but it isn’t possible

and vsintheta-gt=0

=>sintheta=gt/v

Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty

muktesh singh · Answer

Sir how to calculate time, please give detailed solution to this question.

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A target is fixed on top of a pole 13 m high. A person standing at a distance 50 m from the pole is capable of projecting a stone with velocity 10*rootg(underroot 9.8 m/s^2). If his aim is to strike the target in least time what should be the angle of elevation with time

A target is fixed on top of a pole 13 m high. A person standing at a distance 50 m from the pole is capable of projecting a stone with velocity 10*rootg(underroot 9.8 m/s^2). If his aim is to strike the target in least time what should be the angle of elevation with time

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A target is fixed on top of a pole 13 m high. A person standing at a distance 50 m from the pole is capable of projecting a stone with velocity 10*rootg(underroot 9.8 m/s^2). If his aim is to strike the target in least time what should be the angle of elevation with time

A target is fixed on top of a pole 13 m high. A person standing at a distance 50 m from the pole is capable of projecting a stone with velocity 10*rootg(underroot 9.8 m/s^2). If his aim is to strike the target in least time what should be the angle of elevation with time

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