Q.2 let f(x)=x^2+bx+c;where b,c belongs to R. If f(x) is a factor of both x^4+6(x^2)+25 and 3(x^4)+4(x^2)+28x+5,then find the least value of f(x).

all solutions of  of x^4+6(x^2)+25  are imaginary
so if it''s factors are common with 3(x^4)+4(x^2)+28x+5 then all the solutions
will be common which is not possible,the polynomial  3(x^4)+4(x^2)+28x+5 may be  3(x^3)+4(x^2)+28x+5 then only we can solve