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The solution of inequality (x+1)(x2+1)1/2>x2-1 is
(a) {-1} U [2,infinite)
(b) [-1,infinite)
(c){-4}u[2,3]
(d)(-5,infinite)
(x+1)(x2+1)1/2>x2-1
(x+1)(x2+1)1/2>(x-1)(x+1)
either x=-1 or
case 1:x>-1
(x2+1)1/2>x-1
squaring both side,
(x2+1)>x2+1 +2x
therefore x>0
case 2: x<-1
(x2+1)1/2<x-1
therefore, x<0
therefore, answer is [-1,infinte)
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