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Using Langranges mean value theorem for f(x)=cosx we get that |cosa-cosb| is less than or equal to=? A.|a+b| B.|a-b| C.|2a-b| D.|2a+b|

Using Langranges mean value theorem for f(x)=cosx we get that |cosa-cosb| is less than or equal to=?
A.|a+b|
B.|a-b|
C.|2a-b|
D.|2a+b|

Grade:12

1 Answers

Mahesh Neela
24 Points
4 years ago
According to MVT given function is continuous and differentiable then, Derivative if f(c) equal to f(b)-f(a)/ b-a According to this cos b - cos a /b-a equal to -sin c Taking modules on both sides We get lcos a- cos bl equal to lb-al sinc which is less than or equal to la-blTherefore lcos a- cosbl is less or equal to la-bl

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