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# Total number of solution 2x+3x+4x-5x=0 Thanks

Jitender Singh IIT Delhi
7 years ago
Ans:
$f(x) = 2^{x} + 3^{x} + 4^{x} - 5^{x}$
There is only one solution that lie b/w 2 & 3.
$f(2) = 2^{2} + 3^{2} + 4^{2} - 5^{2}$
$f(2) = 4$
$f(3) = 2^{3} + 3^{3} + 4^{3} - 5^{3}$
$f(3) = -26$
So both values have opposite sign, so f(x) should be zero b/w somewhere. You can see it from the graph also.
Thanks & Regards
Jitender Singh
IIT Delhi