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Differential Calculus

Total number of solution 2x+3x+4x-5x=0

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Profile image of vineet nimesh
12 Years agoGrade
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1 Answer

Profile image of Jitender Singh
12 Years ago
Ans:
f(x) = 2^{x} + 3^{x} + 4^{x} - 5^{x}
There is only one solution that lie b/w 2 & 3.
f(2) = 2^{2} + 3^{2} + 4^{2} - 5^{2}
f(2) = 4
f(3) = 2^{3} + 3^{3} + 4^{3} - 5^{3}
f(3) = -26
So both values have opposite sign, so f(x) should be zero b/w somewhere. You can see it from the graph also.
241-851_IF3.gif
Thanks & Regards
Jitender Singh
IIT Delhi
askIITians Faculty

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