Grade 11Differential Calculus
The mimimum value of y=5x2 - 2x +1 is?? The answer is 4/5 but can you explain how?
1 Answer
Vikas TU
Dear Stdent,
Given function as:
Given function as:
y= 5x^2 – 2x + 1
Differntiate it once and equate to zero.
Differntiate it once and equate to zero.
So, dy/dx = 10x -2
For minimum value
10x-2=0
Or, x= 1/5
So, y= 5x1/25 – 2x1/5 + 1
= 1/5-2/5+ 1
= 4/5.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)
Thapar University)
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