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TANGENTS AND NORMALS
find the points on the curve y = x^3 – 2x^2 – 2x at which the tangent lines are parallel to the line y=2x -3

taniska , 10 Years ago
Grade 12
anser 1 Answers
Jitender Singh

Last Activity: 10 Years ago

Ans:
Hello Student,
Please find answer to your question below

Slope of line = 2
y = x^3 - 2x^2 - 2x
y' = 3x^2 - 4x - 2
3x^2 - 4x - 2 = 2
3x^2 - 4x - 4 = 0
(3x+2)(x-2) = 0
x= 2, \frac{-2}{3}
Put in the curve and get y.

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