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Grade 12Differential Calculus

tangents and normals find the equation of the tangent to the curve x^2 + 3y – 3 =0 which is parallel to the line y=4x – 5.

Profile image of taniska
11 Years agoGrade 12
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1 Answer

Profile image of Jitender Singh
11 Years ago
Ans:
Hello Student,
Please find answer to your question below

3y = x^2 - 3
Slope of tangent: y’ = 4
3y' = 2x
3.4 = 2x
x = 6
3y = 6^2 - 3
y = 11
Equation of tangent:
(y-11) = 4(x-6)

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