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Summation upto 10 terms r=1 r/(4r^4+1) summation upto 7 terms r=1 tan^2 {r(pi)}/16

Summation upto 10 terms r=1
r/(4r^4+1)
summation upto 7 terms r=1
tan^2 {r(pi)}/16
 

Grade:11

1 Answers

Nandana
110 Points
4 years ago
hi .. !
        for the first question ,
                   ∑7r=1 r/(4r4 +1)  , by expnding this we get
                        1/5 + 2/65 + 3/ 325 + … 10 / 40001 by looking this series we can understand that first and second terms only yield most significant value & rest of the terms almost negligible , so  the value we obtained is –
                0.230769231 or it is > 0.23 & less than 0.24
 for the second summation , anyway tan (nπ) , n= 1, 2, 3 … is ‘0’
    so the summation also ‘0’ for all ‘r’ .
           
 

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