Grade Select GradeDifferential Calculus
sir please help me solve the ques in the image.this is a question from limits
sir please help me solve the ques in the image.this is a question from limits
2 Answers
Vikas TU
Approved Tutor Answer6 Years agoDear student
= lim logx/(Cosπ/2^x)
lim {log(1+(x-1)}/sin(π/2 - π/2^x)
lim (x-1)/π/2 -π/2^x)
lim(x-1)/π(2^x-1 -1)/2^x)
= 2/πlog2
= lim logx/(Cosπ/2^x)
lim {log(1+(x-1)}/sin(π/2 - π/2^x)
lim (x-1)/π/2 -π/2^x)
lim(x-1)/π(2^x-1 -1)/2^x)
= 2/πlog2
Arun
Dear Shubham
lim {log(1+(x-1)}/sin(π/2 - π/2^x)
lim (x-1)/π/2 -π/2^x)
lim(x-1)/π(2^x-1 -1)/2^x)
= 2/πlog2
lim (x-1)/π/2 -π/2^x)
lim(x-1)/π(2^x-1 -1)/2^x)
= 2/πlog2
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