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Sir explain method of this type concept .........,...................................thanks

```
2 years ago

yathartha gupta
71 Points
```							Given limitx---->0 sin(πx/2)^2x .   & .  [0,2]Put 0 at the place of x Thus limitx------>0 sin 0 =0-------------1Put 2 at the place of x Thus limitx-------->0 sin(2π/2)^4=limitx-------->0(sin(π))^4=0--------------2    Although equation 1 & 2 are same hence the given function will continuous in the given intervel
```
2 years ago
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Course Features

• 51 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions