Pls explain how to solve this question. solution pls

g(a+) means that function is being approached by right hand sidefor limx->a+|x-a|=x-a=a-a=0you can notice that bracket here opens positive.for limx->a-|x-a|=-(x-a)=0here modulus opens as negative as a- is a bit smaller than a, so xis a bit smaller than a so modulus opens as negative so as to give a positive value.in this questionf(x)=|x-a|\Phi(x). let \Phi(x