Please solve question number 53 step by step.....................

note that it can be 1 only if y= ax^2+bx+c= a(x – alpha)(x – beta) is greater than zero.

it holds true in (1), (2), (3).

however, in (4), when a is less than 0 and x0 is less than 1 (which also implies that x0 is less than both alpha and beta), we note that y= a(x – alpha)(x – beta)= a(alpha – x)(beta – x) will be less than 0.

hence, option 4