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please see to the attachment. (from integral calculas arihant)

please see to the attachment. (from integral calculas arihant)
 

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Grade:12

1 Answers

yog
19 Points
4 years ago
2x/2[x]=2h, where x-[x]=h, [x]=n
so,  integral will be ( ∫01 2hdh)×n=n(2-1)/ln2=n/ln2
simply draw the graph 2vs x, as x goes from 0 to 1, 2goes from 20 to 2 with discontuinity at 1. for 1 it again becomes 1. between 1 to 2 it goes from 20 to 2. this will repeat n times. thats integral will become n times area under graph 2 vs x from 0 to 1.

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