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Grade 12Differential Calculus

please explain fully …...please …...hey image attached please tell the method which is used in solution …..please sir .maam …..please anyone …...

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Profile image of milind
11 Years agoGrade 12
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Profile image of Jitender Singh
ApprovedApproved Tutor Answer11 Years ago
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Hello student,
Please find the answer to your question below
[] is greatest integer function.
L = [\frac{3}{4}]+[\frac{3}{4}+\frac{1}{100}]+[\frac{3}{4}+\frac{2}{100}]+............+[\frac{3}{4}+\frac{99}{100}]
[t] = 0, 0 <=t < 1
[t] = 1, 1 <= t < 2
Now looking at the problem in hand
[\frac{3}{4}+\frac{x}{100}] = 0, 0 <= x < 25
[\frac{3}{4}+\frac{x}{100}] = 0, 25 <= x < 99
There are total 100 term in L out of which 25 terms are zero. Rest all the terms are equal to 1. So the sum is 75.