Differential Calculus> Limit x tends to π/2 (Sinx - (sinx)^sinx ...

Limit x tends to π/2 (Sinx - (sinx)^sinx )/(1-sinx + log sinx)Do it without L hospital and taylorexpansionDo it with basics and properties...

Akash Singh , 8 Years ago

Grade 11

1 Answers

Nandana

hi...

for this question procede in this way -

Lim _{x → π/2} (sin x – sinx^{sin x} ) / (1- sin x + log (sin x)) = Lim _{x → π/2} (1- sinx^{sin x -1} )/ (1/ sin x – 1 + log (sin x)/sinx

=1 – sin x^Lim_{x →}π/2 ( sin x) / (1/ sin x – 1 + log (sin x)/sinx

= 1-1 = 0

Last Activity: 8 Years ago

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Differential Calculus> Limit x tends to π/2 (Sinx - (sinx)^sinx ...

Limit x tends to π/2 (Sinx - (sinx)^sinx )/(1-sinx + log sinx)Do it without L hospital and taylorexpansionDo it with basics and properties...

Akash Singh , 8 Years ago

Nandana

LIVE ONLINE CLASSES

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