Vikas TU
Last Activity: 7 Years ago
Dear Student,
f(x) = (x-a)(x-b)(x-c)
f'(x) = (x-a)(x-b) + (x-b)(x-c) + (x-c)(x-a)
f'(x)/f(x) = [(x-a)(x-b) + (x-b)(x-c) + (x-c)(x-a)]/(x-a)(x-b)(x-c) = 1/(x-a) + 1/(x-b) + 1/(x-c).
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)