If f (x)=sin (x) +cos (sqare root of 4-a^2.then,the integral values of a for which f (x) is a periodic function.

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Vikas TU · Answer

Dear student Cos is odd function so square root (4-a^2) is greater than 0 a = 2 , Hope this helps Good Luck

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If f (x)=sin (x) +cos (sqare root of 4-a^2.then,the integral values of a for which f (x) is a periodic function.

If f (x)=sin (x) +cos (sqare root of 4-a^2.then,the integral values of a for which f (x) is a periodic function.

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If f (x)=sin (x) +cos (sqare root of 4-a^2.then,the integral values of a for which f (x) is a periodic function.

If f (x)=sin (x) +cos (sqare root of 4-a^2.then,the integral values of a for which f (x) is a periodic function.

1 Answers

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Other Related Questions on Differential Calculus

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