If 8f(x) + 6f(1/x) = x+ 5 and y= x²f(x), then what will be the value of dy/dx at x= - 1...

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umeshraja · Answer

first solve equation by replacing x by 1/x then you will get f(x)=8x/28-6/28x+10/28 then differentiate after multiplying with x^2

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If 8f(x) + 6f(1/x) = x+ 5 and y= x²f(x), then what will be the value of dy/dx at x= - 1...

If 8f(x) + 6f(1/x) = x+ 5 and y= x²f(x), then what will be the value of dy/dx at x= - 1...

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If 8f(x) + 6f(1/x) = x+ 5 and y= x²f(x), then what will be the value of dy/dx at x= - 1...

If 8f(x) + 6f(1/x) = x+ 5 and y= x²f(x), then what will be the value of dy/dx at x= - 1...

1 Answers

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Other Related Questions on Differential Calculus

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