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I have found k=1 but not able to solve part 2 of the attached question help me sir

I have found k=1 but not able to solve part 2 of the attached question help me sir

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Grade:12

1 Answers

Arun
25758 Points
4 years ago
For 1st part
3 -2 k = 2²/4  - 3
3 - 2k = 1 -3
2k = 5
k = 5/2
Otherpoint at which it should be continuous.
3 - kx = x²/4  - 3
x² + 4kx -24 = 0

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