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How to solve this diffrential calculus problem? Please give solution???
4 months ago

Answers : (1)

Aditya Gupta
2014 Points
							
y= e^(x^2) + 2sinx – 5e^x/3 + 2e
dy/dx = d[e^(x^2)]/dx + d(2sinx)/dx – d(5e^x/3)/dx + d(2e)/dx
now we ll use chain rule and other properties of diff
dy/dx= d[e^(x^2)]/d(x^2) * d(x^2)/dx + 2d(sinx)/dx – 5/3 * d(e^x)/dx + 0
= e^(x^2)*2x + 2cosx – 5/3 * e^x
= 2xe^(x^2) + 2cosx – 5/3 * e^x
kindly approve :)
4 months ago
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