bharat bajaj
Last Activity: 11 Years ago
f(x)= -3sin2x + 2sinx + 4
= -3(sin2x-2/3 sinx)+
=-3(sinx-1/3)^2+3/9+4
=-3(sinx - 1/3)+13/3
Now, for f(x) to be max, the first term should be minimum.
Hence it is at sin x =0
Hence, max. value of f(x) = 16/3
Thanks & Regards
Bharat Bajaj
askIITians Faculty
IIT Delhi