Grade 11Differential Calculus
Find lim x tends to 1 [x^x-1/xlogx]
Find lim x tends to 1 [x^x-1/xlogx]
1 Answer
Abhishek Doyal
when lim tends to 1 it's become 0/0 form
[x^x-1/xlogx] differentiation of x^x-1=x^x(1+log(x))
differentiation ofxlogx=1+log (x)
so by L hospital rule differentiate the fxn
y=x^x(1+log(x))/1+log(x)
put x=1 y=1
limx tends to1=1 ans
Abhishek doyal
IIT Bombay
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