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Grade: 12
        
find dy/dx when
y= sin x sin 2x sin 3x sin 4x
5 years ago

Answers : (3)

Rinkoo Gupta
askIITians Faculty
80 Points
							y=(sinxsin2x)(sin3xsin4x)
taking sinxsin2x as first funtion and sin3xsin4x as second function we apply th e rule of product of two function
dy/dx=sinxsin2x.{sin3x.4cos4x+sin4x3cos3x}+(sin3xsin4x){sinx.2cos2x+sin2xcosx}
=4sinxsin2xsin3xcos4x+3sinxsin2xsin4xcos3x+2sin3xsin4xsinxcos2x+sin3xsin4xsin2xcosx
Thanks & Regards
Rinkoo Gupta
AskIITians Faculty
5 years ago
Arun Kumar
IIT Delhi
askIITians Faculty
256 Points
							
Hello
Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty
5 years ago
Kasinath Sahoo
13 Points
							y= sin x sin 2x sin 3x sin 4xlogy =log (sin x sin 2x sin 3x sin 4x) logy =logsinx +log sin2x +log sin3x +log sin4x Now proceed....... It`s easy
						
2 years ago
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