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y=tan-1{(a+x)/(1-ax)}
dy/dx=1/[1+{(a+x)/(1-ax)}2].[(1-ax).1-(a+x).(-a)]/(1-ax)2
=[1/{(1-ax)2+(a+x)2}].[1-ax+a2+ax]
=(1+a2)/(1+a2x2+a2+x2)
=(1+a2)/(1+a2)(1+x2)
=1/(1+x2)
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Rinkoo Gupta
AskIITians Faculty
Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty
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