A Particle Is Thrown From the bottom of an inclined plane at an inclination of 45° with horizontal as shown Find tan alpha so that it may hit the plane perpendicularly

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Saurabh Koranglekar · Answer

Dear student Please find the link below to theory and similar question https://www.askiitians.com/iit-jee-physics/mechanics/motion-of-projectile.aspx Regards

Vikas TU · Answer

We know that the total displacement perpendicular to the inclined plane is zero So, 0=usin(α−β)t−1/2 g cosβt^2 t = 2usin(α−β)/gcosβ OB = (ucosα)t OA = OB/cosβ = R

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A Particle Is Thrown From the bottom of an inclined plane at an inclination of 45° with horizontal as shown Find tan alpha so that it may hit the plane perpendicularly

A Particle Is Thrown From the bottom of an inclined plane at an inclination of 45° with horizontal as shown
Find tan alpha so that it may hit the plane perpendicularly

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A Particle Is Thrown From the bottom of an inclined plane at an inclination of 45° with horizontal as shown Find tan alpha so that it may hit the plane perpendicularly

A Particle Is Thrown From the bottom of an inclined plane at an inclination of 45° with horizontal as shownFind tan alpha so that it may hit the plane perpendicularly

2 Answers

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Other Related Questions on Differential Calculus

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A Particle Is Thrown From the bottom of an inclined plane at an inclination of 45° with horizontal as shown
Find tan alpha so that it may hit the plane perpendicularly