Badiuddin askIITians.ismu Expert
Last Activity: 15 Years ago
Dear raman malik.
f(x) = cosx+cos{(√2)x}
f'(x)=-sin x -√2 sin √2x =0
it gives x= 2m ∏/(√2 +1 ) and (2m +1 ) ∏ /(√2 -1) where m is any natural number
clearly both values are not multiple of 2∏
only for m=0
and f(0) = 1+1 =2 is its maximum value
so only one solution option b is correct
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