if tangent to the curve root of x+root of y=root of a at a point on it cuts the axes ox and oy at p ang q respectively then op+oq is
Options~
A 2a B a
C 1/2a D none of these

Question

if tangent to the curve root of x+root of y=root of a at a point on it cuts the axes ox and oy at p ang q respectively then op+oq is Options~ A 2a B a C 1/2a D none of these

Bevkoof Singh · Answer

since root x+root y=root a so coordinates when this curve cut x axis (a,0) simil. for y (0,a) so p=a=q thus ans. is (A) 2a

Raj · Answer

√y= √a -√x Now diff. w.r.t to x dy/dx= - √y/√x y - y'/x - x' = -√y/√x Now if it forms triangle then PO^2+OQ^2= PQ^2 Therefore OP =OQ = a PQ = 2a

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if tangent to the curve root of x+root of y=root of a at a point on it cuts the axes ox and oy at p ang q respectively then op+oq is Options~ A 2a B a C 1/2a D none of these

if tangent to the curve root of x+root of y=root of a at a point on it cuts the axes ox and oy at p ang q respectively then op+oq is
Options~
A 2a B a
C 1/2a D none of these

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